0=-16x^2+136x+250

Solution for 0=-16x^2+136x+250 equation:

0=-16x^2+136x+250

We move all terms to the left:

0-(-16x^2+136x+250)=0

We add all the numbers together, and all the variables

-(-16x^2+136x+250)=0

We get rid of parentheses

16x^2-136x-250=0

a = 16; b = -136; c = -250;
Δ = b2-4ac
Δ = -1362-4·16·(-250)
Δ = 34496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{34496}=\sqrt{3136*11}=\sqrt{3136}*\sqrt{11}=56\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-136)-56\sqrt{11}}{2*16}=\frac{136-56\sqrt{11}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-136)+56\sqrt{11}}{2*16}=\frac{136+56\sqrt{11}}{32}
$